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06 Merge Triplets — Interview English Script (C++)

Source aligned with: docs/13_Greedy/06_Merge_Triplets.md

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1) 30-second problem restatement script

English line Traditional Chinese meaning (short) Interview stage
Let me restate merge triplets to target. 我先重述 Merge Triplets 題目。 Restatement
We have many triplets and one target triplet. 題目給多個 triplets 與一個 target。 Restatement
Merge operation takes component-wise maximum of two triplets. merge 操作是逐欄取最大值。 Restatement
We may merge repeatedly in any order. 可任意次、任意順序合併。 Restatement
We need to know whether target can be formed exactly. 要判斷是否能精確形成 target。 Restatement
I will use greedy filtering and component coverage checks. 我會用貪心過濾加欄位覆蓋檢查。 Restatement

2) Clarifying questions (5 lines)

English line Traditional Chinese meaning (short) Interview stage
Do we return boolean only? 是否只回布林值? Clarify
Is merge defined as max per coordinate only? merge 是否僅定義為每欄取 max? Clarify
Can triplets contain values larger than target? triplets 可能出現大於 target 的值嗎? Clarify
Are there constraints large enough to require O(n) scan? 限制是否大到要 O(n) 掃描? Clarify
Is exact equality with target required on all three coordinates? 三個欄位都必須精確等於 target 嗎? Clarify

3) Approach discussion

Brute force (3 lines)

English line Traditional Chinese meaning (short) Interview stage
Brute force explores many subsets and merge orders. 暴力法會探索大量子集合與合併順序。 Approach
Order permutations are unnecessary but still huge search space. 合併順序雖可省但搜尋空間仍龐大。 Approach
We need linear greedy reasoning. 我們需要線性貪心推理。 Approach

Optimized approach (5 lines)

English line Traditional Chinese meaning (short) Interview stage
Any triplet with any coordinate above target is unusable. 任一欄超過 target 的 triplet 都不可用。 Approach
Because max-merge can only keep or increase values, never decrease. 因為 max 合併只會維持或變大,不會變小。 Approach
For usable triplets, track whether each target coordinate can be matched. 對可用 triplet,追蹤三個 target 欄位是否可被匹配。 Approach
If we can match x and y and z coordinates, target is achievable. 若 x、y、z 三欄都能命中,target 可達。 Approach
This needs one pass with constant extra state. 這只需單次掃描與常數額外狀態。 Approach

4) Coding-and-speaking script (line-by-line, in coding order)

English line Traditional Chinese meaning (short) Interview stage
I initialize three flags foundX foundY foundZ as false. 我先把 foundX、foundY、foundZ 初始化為 false。 Coding
I iterate each triplet t in triplets. 我遍歷每個 triplet t。 Coding
If any t coordinate is greater than target coordinate, I skip it. 若 t 任一欄大於 target 對應欄,直接跳過。 Coding
Otherwise this triplet is safe for merging. 否則此 triplet 可安全參與合併。 Coding
If t[0] equals target[0], set foundX true. 若 t[0]==target[0],設 foundX=true。 Coding
If t[1] equals target[1], set foundY true. 若 t[1]==target[1],設 foundY=true。 Coding
If t[2] equals target[2], set foundZ true. 若 t[2]==target[2],設 foundZ=true。 Coding
Return foundX and foundY and foundZ. 回傳 foundX && foundY && foundZ。 Coding

5) Dry-run script using one sample input

English line Traditional Chinese meaning (short) Interview stage
Let me dry-run triplets [[2,5,3],[1,8,4],[1,7,5]] and target [2,7,5]. 我手跑 triplets=[[2,5,3],[1,8,4],[1,7,5]]、target=[2,7,5]。 Dry-run
First triplet is safe and matches target x value two. 第一組可用,命中 x=2。 Dry-run
Second triplet has eight above target y seven, so skip it. 第二組 y=8 超過目標 7,直接跳過。 Dry-run
Third triplet is safe and matches target y and z values. 第三組可用,命中 y 與 z。 Dry-run
Now all three flags become true. 此時三個旗標都為 true。 Dry-run
Therefore target triplet is achievable. 因此 target triplet 可達成。 Dry-run
Final answer is true. 最終答案是 true。 Dry-run

6) Edge/corner test script (at least 4 cases)

English line Traditional Chinese meaning (short) Interview stage
Case one: all triplets exceed target in some coordinate. 案例一:每組都在某欄超過 target。 Edge test
Case two: exact target already appears in input. 案例二:輸入中本來就有 target。 Edge test
Case three: each coordinate available but from different safe triplets. 案例三:三欄分別由不同可用 triplet 提供。 Edge test
Case four: one coordinate can never be matched exactly. 案例四:某一欄永遠無法精確命中。 Edge test
Case five: many duplicates with same safe values. 案例五:大量重複且安全值相同。 Edge test

7) Complexity script

Short version (2 lines)

English line Traditional Chinese meaning (short) Interview stage
Time complexity is O(n). 時間複雜度是 O(n)。 Complexity
Space complexity is O(1). 空間複雜度是 O(1)。 Complexity

Full version (4 lines)

English line Traditional Chinese meaning (short) Interview stage
We scan each triplet exactly once. 每個 triplet 只掃描一次。 Complexity
Per triplet work is constant coordinate checks and flag updates. 每組只做常數次欄位檢查與旗標更新。 Complexity
Therefore runtime is O(n). 因此時間是 O(n)。 Complexity
We store only three booleans, so memory is O(1). 只儲存三個布林值,空間 O(1)。 Complexity

8) If stuck rescue lines (10 lines)

English line Traditional Chinese meaning (short) Interview stage
Let me first remove impossible triplets. 我先排除不可能使用的 triplet。 If stuck
Any coordinate above target is toxic. 任一欄超過 target 都是有毒資料。 If stuck
Max merge cannot reduce an oversized coordinate. max 合併無法把過大的欄位降回來。 If stuck
So only safe triplets should be considered. 所以只能考慮安全 triplet。 If stuck
Then I just need coordinate coverage checks. 接著只需做欄位覆蓋檢查。 If stuck
Need one safe triplet matching target x. 需要至少一組安全 triplet 命中 target x。 If stuck
Similarly for y and z. y 與 z 也是同理。 If stuck
Let me test one failing case where z cannot be matched. 我測一個 z 永遠命不中的失敗案例。 If stuck
Flags show missing z so answer is false. 旗標顯示缺 z,所以答案 false。 If stuck
Great, proof and implementation are aligned. 很好,證明與實作一致。 If stuck

9) Final wrap-up lines (5 lines)

English line Traditional Chinese meaning (short) Interview stage
I solved merge triplets with greedy filtering. 我用貪心過濾解了 Merge Triplets。 Wrap-up
Oversized triplets are discarded immediately. 超標 triplet 會立刻丟棄。 Wrap-up
Safe triplets only need to cover target coordinates. 可用 triplet 只需覆蓋目標三欄。 Wrap-up
Complexity is O(n) time and O(1) space. 複雜度是 O(n) 時間、O(1) 空間。 Wrap-up
This is concise and interview-friendly. 這個解法簡潔且面試友善。 Wrap-up

10) Ultra-short cheat sheet (20 lines total)

English line Traditional Chinese meaning (short) Interview stage
Goal: can merges form exact target triplet. 目標:合併後能否精確得到 target。 Cheat sheet
Merge uses coordinate-wise max. merge 是逐欄取 max。 Cheat sheet
Filter out triplets exceeding target in any coordinate. 任一欄超標的 triplet 直接過濾。 Cheat sheet
Oversized values can never be fixed later. 超標值後續不可能被修正。 Cheat sheet
Track foundX, foundY, foundZ. 追蹤 foundX、foundY、foundZ。 Cheat sheet
For each safe triplet, update matching flags. 每個安全 triplet 更新命中旗標。 Cheat sheet
If t[0]==target[0], foundX=true. 若 t[0]==target[0],foundX=true。 Cheat sheet
If t[1]==target[1], foundY=true. 若 t[1]==target[1],foundY=true。 Cheat sheet
If t[2]==target[2], foundZ=true. 若 t[2]==target[2],foundZ=true。 Cheat sheet
Final answer is foundX&&foundY&&foundZ. 最終答案是 foundX&&foundY&&foundZ。 Cheat sheet
One pass through triplets. 單次掃描 triplets。 Cheat sheet
Time O(n). 時間 O(n)。 Cheat sheet
Space O(1). 空間 O(1)。 Cheat sheet
Common bug: not filtering oversized triplets. 常見錯誤:沒先過濾超標 triplet。 Cheat sheet
Common bug: expecting one triplet to match all coordinates. 常見錯誤:誤以為單一 triplet 要全欄命中。 Cheat sheet
Coordinates can be contributed by different triplets. 三欄可由不同 triplet 貢獻。 Cheat sheet
Exact match required for each coordinate. 每個欄位都要精確命中。 Cheat sheet
Safe triplets can be merged in any order. 安全 triplet 合併順序不影響結論。 Cheat sheet
Validate with one impossible coordinate case. 記得驗證某欄永遠不可達案例。 Cheat sheet
Keep explanation focused on monotonic max property. 說明聚焦在 max 的單調性。 Cheat sheet

Quality check

  • Consistency with source solution: ✅ Toxic-filter + coordinate coverage logic preserved.
  • No hallucinated constraints: ✅ Merge semantics and exact-target requirement maintained.
  • Language simplicity: ✅ Straightforward interview explanation tied to max monotonicity.